3.8.6 \(\int \frac {A+B x}{\sqrt {x} (a^2+2 a b x+b^2 x^2)^3} \, dx\)

Optimal. Leaf size=190 \[ \frac {7 (a B+9 A b) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{128 a^{11/2} b^{3/2}}+\frac {7 \sqrt {x} (a B+9 A b)}{128 a^5 b (a+b x)}+\frac {7 \sqrt {x} (a B+9 A b)}{192 a^4 b (a+b x)^2}+\frac {7 \sqrt {x} (a B+9 A b)}{240 a^3 b (a+b x)^3}+\frac {\sqrt {x} (a B+9 A b)}{40 a^2 b (a+b x)^4}+\frac {\sqrt {x} (A b-a B)}{5 a b (a+b x)^5} \]

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Rubi [A]  time = 0.08, antiderivative size = 190, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 5, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.172, Rules used = {27, 78, 51, 63, 205} \begin {gather*} \frac {7 (a B+9 A b) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{128 a^{11/2} b^{3/2}}+\frac {7 \sqrt {x} (a B+9 A b)}{128 a^5 b (a+b x)}+\frac {7 \sqrt {x} (a B+9 A b)}{192 a^4 b (a+b x)^2}+\frac {7 \sqrt {x} (a B+9 A b)}{240 a^3 b (a+b x)^3}+\frac {\sqrt {x} (a B+9 A b)}{40 a^2 b (a+b x)^4}+\frac {\sqrt {x} (A b-a B)}{5 a b (a+b x)^5} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(A + B*x)/(Sqrt[x]*(a^2 + 2*a*b*x + b^2*x^2)^3),x]

[Out]

((A*b - a*B)*Sqrt[x])/(5*a*b*(a + b*x)^5) + ((9*A*b + a*B)*Sqrt[x])/(40*a^2*b*(a + b*x)^4) + (7*(9*A*b + a*B)*
Sqrt[x])/(240*a^3*b*(a + b*x)^3) + (7*(9*A*b + a*B)*Sqrt[x])/(192*a^4*b*(a + b*x)^2) + (7*(9*A*b + a*B)*Sqrt[x
])/(128*a^5*b*(a + b*x)) + (7*(9*A*b + a*B)*ArcTan[(Sqrt[b]*Sqrt[x])/Sqrt[a]])/(128*a^(11/2)*b^(3/2))

Rule 27

Int[(u_.)*((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[u*Cancel[(b/2 + c*x)^(2*p)/c^p], x] /; Fr
eeQ[{a, b, c}, x] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p]

Rule 51

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*(m + n + 2))/((b*c - a*d)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^n,
x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && LtQ[m, -1] &&  !(LtQ[n, -1] && (EqQ[a, 0] || (NeQ[
c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 78

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> -Simp[((b*e - a*f
)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(f*(p + 1)*(c*f - d*e)), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1)
+ c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f,
n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || IntegerQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || LtQ
[p, n]))))

Rule 205

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]*ArcTan[x/Rt[a/b, 2]])/a, x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rubi steps

\begin {align*} \int \frac {A+B x}{\sqrt {x} \left (a^2+2 a b x+b^2 x^2\right )^3} \, dx &=\int \frac {A+B x}{\sqrt {x} (a+b x)^6} \, dx\\ &=\frac {(A b-a B) \sqrt {x}}{5 a b (a+b x)^5}+\frac {(9 A b+a B) \int \frac {1}{\sqrt {x} (a+b x)^5} \, dx}{10 a b}\\ &=\frac {(A b-a B) \sqrt {x}}{5 a b (a+b x)^5}+\frac {(9 A b+a B) \sqrt {x}}{40 a^2 b (a+b x)^4}+\frac {(7 (9 A b+a B)) \int \frac {1}{\sqrt {x} (a+b x)^4} \, dx}{80 a^2 b}\\ &=\frac {(A b-a B) \sqrt {x}}{5 a b (a+b x)^5}+\frac {(9 A b+a B) \sqrt {x}}{40 a^2 b (a+b x)^4}+\frac {7 (9 A b+a B) \sqrt {x}}{240 a^3 b (a+b x)^3}+\frac {(7 (9 A b+a B)) \int \frac {1}{\sqrt {x} (a+b x)^3} \, dx}{96 a^3 b}\\ &=\frac {(A b-a B) \sqrt {x}}{5 a b (a+b x)^5}+\frac {(9 A b+a B) \sqrt {x}}{40 a^2 b (a+b x)^4}+\frac {7 (9 A b+a B) \sqrt {x}}{240 a^3 b (a+b x)^3}+\frac {7 (9 A b+a B) \sqrt {x}}{192 a^4 b (a+b x)^2}+\frac {(7 (9 A b+a B)) \int \frac {1}{\sqrt {x} (a+b x)^2} \, dx}{128 a^4 b}\\ &=\frac {(A b-a B) \sqrt {x}}{5 a b (a+b x)^5}+\frac {(9 A b+a B) \sqrt {x}}{40 a^2 b (a+b x)^4}+\frac {7 (9 A b+a B) \sqrt {x}}{240 a^3 b (a+b x)^3}+\frac {7 (9 A b+a B) \sqrt {x}}{192 a^4 b (a+b x)^2}+\frac {7 (9 A b+a B) \sqrt {x}}{128 a^5 b (a+b x)}+\frac {(7 (9 A b+a B)) \int \frac {1}{\sqrt {x} (a+b x)} \, dx}{256 a^5 b}\\ &=\frac {(A b-a B) \sqrt {x}}{5 a b (a+b x)^5}+\frac {(9 A b+a B) \sqrt {x}}{40 a^2 b (a+b x)^4}+\frac {7 (9 A b+a B) \sqrt {x}}{240 a^3 b (a+b x)^3}+\frac {7 (9 A b+a B) \sqrt {x}}{192 a^4 b (a+b x)^2}+\frac {7 (9 A b+a B) \sqrt {x}}{128 a^5 b (a+b x)}+\frac {(7 (9 A b+a B)) \operatorname {Subst}\left (\int \frac {1}{a+b x^2} \, dx,x,\sqrt {x}\right )}{128 a^5 b}\\ &=\frac {(A b-a B) \sqrt {x}}{5 a b (a+b x)^5}+\frac {(9 A b+a B) \sqrt {x}}{40 a^2 b (a+b x)^4}+\frac {7 (9 A b+a B) \sqrt {x}}{240 a^3 b (a+b x)^3}+\frac {7 (9 A b+a B) \sqrt {x}}{192 a^4 b (a+b x)^2}+\frac {7 (9 A b+a B) \sqrt {x}}{128 a^5 b (a+b x)}+\frac {7 (9 A b+a B) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{128 a^{11/2} b^{3/2}}\\ \end {align*}

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Mathematica [C]  time = 0.03, size = 59, normalized size = 0.31 \begin {gather*} \frac {\sqrt {x} \left (\frac {a^5 (A b-a B)}{(a+b x)^5}+(a B+9 A b) \, _2F_1\left (\frac {1}{2},5;\frac {3}{2};-\frac {b x}{a}\right )\right )}{5 a^6 b} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(A + B*x)/(Sqrt[x]*(a^2 + 2*a*b*x + b^2*x^2)^3),x]

[Out]

(Sqrt[x]*((a^5*(A*b - a*B))/(a + b*x)^5 + (9*A*b + a*B)*Hypergeometric2F1[1/2, 5, 3/2, -((b*x)/a)]))/(5*a^6*b)

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IntegrateAlgebraic [A]  time = 0.24, size = 184, normalized size = 0.97 \begin {gather*} \frac {7 (a B+9 A b) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{128 a^{11/2} b^{3/2}}+\frac {-105 a^5 B \sqrt {x}+2895 a^4 A b \sqrt {x}+790 a^4 b B x^{3/2}+7110 a^3 A b^2 x^{3/2}+896 a^3 b^2 B x^{5/2}+8064 a^2 A b^3 x^{5/2}+490 a^2 b^3 B x^{7/2}+4410 a A b^4 x^{7/2}+105 a b^4 B x^{9/2}+945 A b^5 x^{9/2}}{1920 a^5 b (a+b x)^5} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(A + B*x)/(Sqrt[x]*(a^2 + 2*a*b*x + b^2*x^2)^3),x]

[Out]

(2895*a^4*A*b*Sqrt[x] - 105*a^5*B*Sqrt[x] + 7110*a^3*A*b^2*x^(3/2) + 790*a^4*b*B*x^(3/2) + 8064*a^2*A*b^3*x^(5
/2) + 896*a^3*b^2*B*x^(5/2) + 4410*a*A*b^4*x^(7/2) + 490*a^2*b^3*B*x^(7/2) + 945*A*b^5*x^(9/2) + 105*a*b^4*B*x
^(9/2))/(1920*a^5*b*(a + b*x)^5) + (7*(9*A*b + a*B)*ArcTan[(Sqrt[b]*Sqrt[x])/Sqrt[a]])/(128*a^(11/2)*b^(3/2))

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fricas [A]  time = 0.45, size = 637, normalized size = 3.35 \begin {gather*} \left [-\frac {105 \, {\left (B a^{6} + 9 \, A a^{5} b + {\left (B a b^{5} + 9 \, A b^{6}\right )} x^{5} + 5 \, {\left (B a^{2} b^{4} + 9 \, A a b^{5}\right )} x^{4} + 10 \, {\left (B a^{3} b^{3} + 9 \, A a^{2} b^{4}\right )} x^{3} + 10 \, {\left (B a^{4} b^{2} + 9 \, A a^{3} b^{3}\right )} x^{2} + 5 \, {\left (B a^{5} b + 9 \, A a^{4} b^{2}\right )} x\right )} \sqrt {-a b} \log \left (\frac {b x - a - 2 \, \sqrt {-a b} \sqrt {x}}{b x + a}\right ) + 2 \, {\left (105 \, B a^{6} b - 2895 \, A a^{5} b^{2} - 105 \, {\left (B a^{2} b^{5} + 9 \, A a b^{6}\right )} x^{4} - 490 \, {\left (B a^{3} b^{4} + 9 \, A a^{2} b^{5}\right )} x^{3} - 896 \, {\left (B a^{4} b^{3} + 9 \, A a^{3} b^{4}\right )} x^{2} - 790 \, {\left (B a^{5} b^{2} + 9 \, A a^{4} b^{3}\right )} x\right )} \sqrt {x}}{3840 \, {\left (a^{6} b^{7} x^{5} + 5 \, a^{7} b^{6} x^{4} + 10 \, a^{8} b^{5} x^{3} + 10 \, a^{9} b^{4} x^{2} + 5 \, a^{10} b^{3} x + a^{11} b^{2}\right )}}, -\frac {105 \, {\left (B a^{6} + 9 \, A a^{5} b + {\left (B a b^{5} + 9 \, A b^{6}\right )} x^{5} + 5 \, {\left (B a^{2} b^{4} + 9 \, A a b^{5}\right )} x^{4} + 10 \, {\left (B a^{3} b^{3} + 9 \, A a^{2} b^{4}\right )} x^{3} + 10 \, {\left (B a^{4} b^{2} + 9 \, A a^{3} b^{3}\right )} x^{2} + 5 \, {\left (B a^{5} b + 9 \, A a^{4} b^{2}\right )} x\right )} \sqrt {a b} \arctan \left (\frac {\sqrt {a b}}{b \sqrt {x}}\right ) + {\left (105 \, B a^{6} b - 2895 \, A a^{5} b^{2} - 105 \, {\left (B a^{2} b^{5} + 9 \, A a b^{6}\right )} x^{4} - 490 \, {\left (B a^{3} b^{4} + 9 \, A a^{2} b^{5}\right )} x^{3} - 896 \, {\left (B a^{4} b^{3} + 9 \, A a^{3} b^{4}\right )} x^{2} - 790 \, {\left (B a^{5} b^{2} + 9 \, A a^{4} b^{3}\right )} x\right )} \sqrt {x}}{1920 \, {\left (a^{6} b^{7} x^{5} + 5 \, a^{7} b^{6} x^{4} + 10 \, a^{8} b^{5} x^{3} + 10 \, a^{9} b^{4} x^{2} + 5 \, a^{10} b^{3} x + a^{11} b^{2}\right )}}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/(b^2*x^2+2*a*b*x+a^2)^3/x^(1/2),x, algorithm="fricas")

[Out]

[-1/3840*(105*(B*a^6 + 9*A*a^5*b + (B*a*b^5 + 9*A*b^6)*x^5 + 5*(B*a^2*b^4 + 9*A*a*b^5)*x^4 + 10*(B*a^3*b^3 + 9
*A*a^2*b^4)*x^3 + 10*(B*a^4*b^2 + 9*A*a^3*b^3)*x^2 + 5*(B*a^5*b + 9*A*a^4*b^2)*x)*sqrt(-a*b)*log((b*x - a - 2*
sqrt(-a*b)*sqrt(x))/(b*x + a)) + 2*(105*B*a^6*b - 2895*A*a^5*b^2 - 105*(B*a^2*b^5 + 9*A*a*b^6)*x^4 - 490*(B*a^
3*b^4 + 9*A*a^2*b^5)*x^3 - 896*(B*a^4*b^3 + 9*A*a^3*b^4)*x^2 - 790*(B*a^5*b^2 + 9*A*a^4*b^3)*x)*sqrt(x))/(a^6*
b^7*x^5 + 5*a^7*b^6*x^4 + 10*a^8*b^5*x^3 + 10*a^9*b^4*x^2 + 5*a^10*b^3*x + a^11*b^2), -1/1920*(105*(B*a^6 + 9*
A*a^5*b + (B*a*b^5 + 9*A*b^6)*x^5 + 5*(B*a^2*b^4 + 9*A*a*b^5)*x^4 + 10*(B*a^3*b^3 + 9*A*a^2*b^4)*x^3 + 10*(B*a
^4*b^2 + 9*A*a^3*b^3)*x^2 + 5*(B*a^5*b + 9*A*a^4*b^2)*x)*sqrt(a*b)*arctan(sqrt(a*b)/(b*sqrt(x))) + (105*B*a^6*
b - 2895*A*a^5*b^2 - 105*(B*a^2*b^5 + 9*A*a*b^6)*x^4 - 490*(B*a^3*b^4 + 9*A*a^2*b^5)*x^3 - 896*(B*a^4*b^3 + 9*
A*a^3*b^4)*x^2 - 790*(B*a^5*b^2 + 9*A*a^4*b^3)*x)*sqrt(x))/(a^6*b^7*x^5 + 5*a^7*b^6*x^4 + 10*a^8*b^5*x^3 + 10*
a^9*b^4*x^2 + 5*a^10*b^3*x + a^11*b^2)]

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giac [A]  time = 0.18, size = 155, normalized size = 0.82 \begin {gather*} \frac {7 \, {\left (B a + 9 \, A b\right )} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{128 \, \sqrt {a b} a^{5} b} + \frac {105 \, B a b^{4} x^{\frac {9}{2}} + 945 \, A b^{5} x^{\frac {9}{2}} + 490 \, B a^{2} b^{3} x^{\frac {7}{2}} + 4410 \, A a b^{4} x^{\frac {7}{2}} + 896 \, B a^{3} b^{2} x^{\frac {5}{2}} + 8064 \, A a^{2} b^{3} x^{\frac {5}{2}} + 790 \, B a^{4} b x^{\frac {3}{2}} + 7110 \, A a^{3} b^{2} x^{\frac {3}{2}} - 105 \, B a^{5} \sqrt {x} + 2895 \, A a^{4} b \sqrt {x}}{1920 \, {\left (b x + a\right )}^{5} a^{5} b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/(b^2*x^2+2*a*b*x+a^2)^3/x^(1/2),x, algorithm="giac")

[Out]

7/128*(B*a + 9*A*b)*arctan(b*sqrt(x)/sqrt(a*b))/(sqrt(a*b)*a^5*b) + 1/1920*(105*B*a*b^4*x^(9/2) + 945*A*b^5*x^
(9/2) + 490*B*a^2*b^3*x^(7/2) + 4410*A*a*b^4*x^(7/2) + 896*B*a^3*b^2*x^(5/2) + 8064*A*a^2*b^3*x^(5/2) + 790*B*
a^4*b*x^(3/2) + 7110*A*a^3*b^2*x^(3/2) - 105*B*a^5*sqrt(x) + 2895*A*a^4*b*sqrt(x))/((b*x + a)^5*a^5*b)

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maple [A]  time = 0.07, size = 150, normalized size = 0.79 \begin {gather*} \frac {63 A \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{128 \sqrt {a b}\, a^{5}}+\frac {7 B \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{128 \sqrt {a b}\, a^{4} b}+\frac {\frac {7 \left (9 A b +B a \right ) b^{3} x^{\frac {9}{2}}}{128 a^{5}}+\frac {49 \left (9 A b +B a \right ) b^{2} x^{\frac {7}{2}}}{192 a^{4}}+\frac {7 \left (9 A b +B a \right ) b \,x^{\frac {5}{2}}}{15 a^{3}}+\frac {79 \left (9 A b +B a \right ) x^{\frac {3}{2}}}{192 a^{2}}+\frac {\left (193 A b -7 B a \right ) \sqrt {x}}{128 a b}}{\left (b x +a \right )^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((B*x+A)/(b^2*x^2+2*a*b*x+a^2)^3/x^(1/2),x)

[Out]

2*(7/256*(9*A*b+B*a)/a^5*b^3*x^(9/2)+49/384/a^4*b^2*(9*A*b+B*a)*x^(7/2)+7/30/a^3*(9*A*b+B*a)*b*x^(5/2)+79/384/
a^2*(9*A*b+B*a)*x^(3/2)+1/256*(193*A*b-7*B*a)/a/b*x^(1/2))/(b*x+a)^5+63/128/a^5/(a*b)^(1/2)*arctan(1/(a*b)^(1/
2)*b*x^(1/2))*A+7/128/a^4/b/(a*b)^(1/2)*arctan(1/(a*b)^(1/2)*b*x^(1/2))*B

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maxima [A]  time = 1.19, size = 198, normalized size = 1.04 \begin {gather*} \frac {105 \, {\left (B a b^{4} + 9 \, A b^{5}\right )} x^{\frac {9}{2}} + 490 \, {\left (B a^{2} b^{3} + 9 \, A a b^{4}\right )} x^{\frac {7}{2}} + 896 \, {\left (B a^{3} b^{2} + 9 \, A a^{2} b^{3}\right )} x^{\frac {5}{2}} + 790 \, {\left (B a^{4} b + 9 \, A a^{3} b^{2}\right )} x^{\frac {3}{2}} - 15 \, {\left (7 \, B a^{5} - 193 \, A a^{4} b\right )} \sqrt {x}}{1920 \, {\left (a^{5} b^{6} x^{5} + 5 \, a^{6} b^{5} x^{4} + 10 \, a^{7} b^{4} x^{3} + 10 \, a^{8} b^{3} x^{2} + 5 \, a^{9} b^{2} x + a^{10} b\right )}} + \frac {7 \, {\left (B a + 9 \, A b\right )} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{128 \, \sqrt {a b} a^{5} b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/(b^2*x^2+2*a*b*x+a^2)^3/x^(1/2),x, algorithm="maxima")

[Out]

1/1920*(105*(B*a*b^4 + 9*A*b^5)*x^(9/2) + 490*(B*a^2*b^3 + 9*A*a*b^4)*x^(7/2) + 896*(B*a^3*b^2 + 9*A*a^2*b^3)*
x^(5/2) + 790*(B*a^4*b + 9*A*a^3*b^2)*x^(3/2) - 15*(7*B*a^5 - 193*A*a^4*b)*sqrt(x))/(a^5*b^6*x^5 + 5*a^6*b^5*x
^4 + 10*a^7*b^4*x^3 + 10*a^8*b^3*x^2 + 5*a^9*b^2*x + a^10*b) + 7/128*(B*a + 9*A*b)*arctan(b*sqrt(x)/sqrt(a*b))
/(sqrt(a*b)*a^5*b)

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mupad [B]  time = 1.24, size = 172, normalized size = 0.91 \begin {gather*} \frac {\frac {79\,x^{3/2}\,\left (9\,A\,b+B\,a\right )}{192\,a^2}+\frac {49\,b^2\,x^{7/2}\,\left (9\,A\,b+B\,a\right )}{192\,a^4}+\frac {7\,b^3\,x^{9/2}\,\left (9\,A\,b+B\,a\right )}{128\,a^5}+\frac {\sqrt {x}\,\left (193\,A\,b-7\,B\,a\right )}{128\,a\,b}+\frac {7\,b\,x^{5/2}\,\left (9\,A\,b+B\,a\right )}{15\,a^3}}{a^5+5\,a^4\,b\,x+10\,a^3\,b^2\,x^2+10\,a^2\,b^3\,x^3+5\,a\,b^4\,x^4+b^5\,x^5}+\frac {7\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {x}}{\sqrt {a}}\right )\,\left (9\,A\,b+B\,a\right )}{128\,a^{11/2}\,b^{3/2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((A + B*x)/(x^(1/2)*(a^2 + b^2*x^2 + 2*a*b*x)^3),x)

[Out]

((79*x^(3/2)*(9*A*b + B*a))/(192*a^2) + (49*b^2*x^(7/2)*(9*A*b + B*a))/(192*a^4) + (7*b^3*x^(9/2)*(9*A*b + B*a
))/(128*a^5) + (x^(1/2)*(193*A*b - 7*B*a))/(128*a*b) + (7*b*x^(5/2)*(9*A*b + B*a))/(15*a^3))/(a^5 + b^5*x^5 +
5*a*b^4*x^4 + 10*a^3*b^2*x^2 + 10*a^2*b^3*x^3 + 5*a^4*b*x) + (7*atan((b^(1/2)*x^(1/2))/a^(1/2))*(9*A*b + B*a))
/(128*a^(11/2)*b^(3/2))

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/(b**2*x**2+2*a*b*x+a**2)**3/x**(1/2),x)

[Out]

Timed out

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